Molarity = number of moles/number of litres
Moles= molarity * number of litres <- this is what we use for finding the limiting reagent!
Litres = number of moles/molarity
Litres just means grams when we are using it in our case for limiting reagents
Mole: measure of amount of chemical substance
Molar is the unit -> M
Unit for molarity = molar
Here are some examples of how you would do a type of problem like this:
1. What is the molarity of a solution of potassium chloride which contains 1.35 moles of solute in a total volume of 0.716L?
- 1.35/0.716 = 1.89L
2. How many moles are in 352mL of a 1.73M solution of NH4NO3?
- Volume = 0.352L
- Number of moles = molarity * number of litres
- 0.352 * 1.73 = 0.61 mol
3. What volume in mL of a 0.241M solution of sodium chloride would be required if you wanted 0.200moles of solute?
- Number of litres = number of moles/ molarity
- 0.200/0.241= 0.831
- 0.831 * 1000 = 831 mL
4. How many moles are in 0.408L of a 0.685M solution of sodium iodide?
- number of moles = molarity * number of litres
- 0.685 * 0.408 = 0.28 mol
5. What volume in L of a 0.688M solution of lithium iodide would be required if you wanted 0.142moles of solute?
- Number of litres = number of moles/ molarity
- 0.142/ 0.688 = 0.206 L