theoretical yield answers page

Here are the answers to the questions for detailed answers look below...

click here if you are getting these wrong to learn again how to find the theoretical yield...

1.    96.624g

2. 36.32g

3. 0.776g

4. 21.24g

5. 13.15g

6. 72g

7. 173.72g

8. 176.08g

Detailed answers:

QUESTION 1:

Steps to follow:

Find limiting reagent,

Molar mass of C2H3F = 46

Molar mass of O2 = 32

50.5/46 = 1.098 mol

118/32 = 3.69 mol

2:5

1:2.5

limiting reagent = C2H3F

If you didn’t get this click here to go back to learning limiting reagents

Molar mass of CO2= 44

1.98     * 44 = 48.312

ratio: 2:4, 1:2

2*48.312 = 96.624 grams

QUESTION 2

Steps to follow:

Find limiting reagent,

Molar mass of C₂H₅NSCl = 117.5

Molar mass of O₂ = 32

7.76/117.5 = 0.66 mol

7.25/32 = 0.227 mol

1:9

limiting reagent = C₂H₅NSCl

If you didn’t get this click here to go back to learning limiting reagents

Molar mass of SO₃= 80

0.227     * 80 = 18.16

ratio: 1:2

2*18.16 = 36.32 grams

QUESTION 3

Find limiting reagent,

Molar mass of C₂H₄0₂ = 60

Molar mass of O₂ = 32

98.6/60 = 1.64 mol

138/32 = 0.043 mol

1:2

limiting reagent = O₂

If you didn’t get this click here to go back to learning limiting reagents

Molar mass of H₂O= 18

0.043 * 18 = 0.776

ratio: 1:1

= 0.776 grams

QUESTION 4:

Find limiting reagent,

Molar mass of C₂H₄N = 38

Molar mass of O2 = 32

33/38 = 0.868 mol

75.5/32 = 2.36 mol

1:2

limiting reagent = O₂

If you didn’t get this click here to go back to learning limiting reagents

Molar mass of H₂O= 18

2.36     * 18 = 42.48

ratio: 4:2, 1:0.5

0.5*42.48= 21.24 grams

QUESTION 5:

Find limiting reagent,

Molar mass of C₆H₆ = 78

Molar mass of O2 = 32

36.3/78 = 0.465 mol

35.1/32 = 1.097 mol

2:9

1:4.5

limiting reagent = O₂

If you didn’t get this click here to go back to learning limiting reagents

Molar mass of H₂O= 18

1.097     * 18 = 19.7

ratio: 9:6, 1:0.666

0.666*19.7= 13.15 grams

QUESTION 6:

Find limiting reagent,

Molar mass of SO₂ = 64

Molar mass of O2 = 32

57.6/64 = 0.9 mol

19.3/32 = 0.6 mol

2:1

limiting reagent = SO₂

If you didn’t get this click here to go back to learning limiting reagents

Molar mass of SO₃= 80

0.9 * 80 = 72

ratio: 1:1

= 72 grams

QUESTION 7:

Find limiting reagent,

Molar mass of H₂ = 2

Molar mass of Cl₂ = 71

18.6/2 = 9.3 mol

487/71 = 6.86 mol

1:1

limiting reagent = Cl₂

If you didn’t get this click here to go back to learning limiting reagents

Molar mass of HCl = 80

6.86 * 80 = 86.86

ratio: 1:2

2*86.86

= 173.72 grams

QUESTION 8:

Find limiting reagent,

Molar mass of P₄ = 124

Molar mass of O₂ = 32

77.1/124 = 0.62 mol

129/32 = 4.03 mol

1:5

limiting reagent = P₄

If you didn’t get this click here to go back to learning limiting reagents

Molar mass of P₄O₁₀ = 284

0.62* 284 = 176.08

ratio: 1:1

= 176.08 grams