FINDING THE LIMITIGN REAGENT ANSWERS: INCORRECT
Here are steps 1-5 I will take for every problem: 1. Write down two pieces of information given 2. Find the molar mass of each given piece of information If it is this you seem to keep getting wrong click here for help… 3. Divide the masses given in the equation by the molar masses you just found to find the moles If it is this you seem to keep getting wrong click here for help… 4. Compare ratios If it is this you seem to keep getting wrong click here for help… 5. Multiply out if needed and find the limiting reagent If it is this you seem to keep getting wrong click here for help… ANSWER QUESTION 1 1. 1. 79.4 grams of HCl 11.5 grams of O2 2. molar mass of HCl: 36.5 molar mass of O2: 32 3. HCl: 79.4/36.5 = 2.18 O2: 11.5/32 = 0.36 4. 4:1 5. 4:1, always make left side 1 so divide both sides by 4. New ratio is 1:0.25 HCl:O2 1:0.25 2.18:0.36 O2 is obviously the limiting reagent ANSWER QUESTION 2 1. 9.06 grams of Al 48.8 grams of HCl 2. molar mass of Al: 27 molar mass of HCl: 36.5 3. Al: 9.06/27 = 0.34 HCl: 48.8/36.5 = 1.34 4. 2:6 5. 2:6, always make left side 1 so divide both sides by 2. New ratio is 1:3 Al:HCl 1:3 0.34:1.34 Al is obviously the limiting reagent ANSWER QUESTION 3 1. 77.3 grams of C2H5OH 268 grams of O2 2. molar mass of C2H5OH: 46 molar mass of O2: 32 3. C2H5OH: 77.3/46 = 1.68 O2: 268/32 = 8.375 4. 2:6 5. 2:6, always make left side 1 so divide both sides by 2. New ratio is 1:3 C2H5OH:O2 1:3 1.68:8.375 C2H5OH is obviously the limiting reagent ANSWER QUESTION 4
1. 23.8 grams of CS2 111 grams of Cl2 2. molar mass of CS2: 76 molar mass of Cl2: 71 3. CS2: 23.8/76 = 0.313 Cl2: 111/71 = 1.56 4. 1:3 5. 1:3, always make left side 1 so this is already good. CS2:Cl2 1:3 0.313:1.56 CS2 is obviously the limiting reagent ANSWER QUESTION 5
1. 84.0 grams of C4H8O 263 grams of O2 2. molar mass of C4H8O: 72 molar mass of O2: 32 3. C4H8O: 84/72 = 1.167 O2: 263/32 = 8.22 4. 2:11 5. 2:11, always make left side 1 so divide each side by 2 and the new ratio is 1: 5.5 C4H8O:O2 1:5.5 1.167:8.22 C4H8O is obviously the limiting reagent ANSWER QUESTION 6
1. 55.3 grams of ZnS 18.4 grams of O2 2. molar mass of ZnS: 97 molar mass of O2: 32 3. ZnS: 55.3/97 = 0.57 O2: 18.4/32 = 0.575 4. 2:3 5. 2:3, always make left side 1 so divide each side by 2 and the new ratio is 1: 1.5 ZnS:O2 1:1.5 0.57:0.575 O2 is obviously the limiting reagent ANSWER QUESTION 7
1. 56.5 grams of CO 16.0 grams of H2 2. molar mass of CO: 28 molar mass of H2: 2 3. CO: 56.5/28 = 2.02 H2: 16/2 = 8 4. 3:7 5. 3:7, always make left side 1 so divide each side by 3 and the new ratio is 1: 2.33 CO:H2 1:2.33 2.02:8 CO is obviously the limiting reagent ANSWER QUESTION 8
1. 44.4 grams of N2 148 grams of H2O 2. molar mass of N2: 28 molar mass of H2O : 18 3. N2: 44.4/28 = 1.6 H2O: 148/18 = 8.22 4. 1:4 5. 1:4, always make left side 1, but luckily here it already is 1! N2:H2O 1:4 1.6:8.22 N2 is obviously the limiting reagent ANSWER QUESTION 9
1. 61.4 grams of C2H5Cl2 84.6 grams of O2 2. molar mass of C2H5Cl2: 100 molar mass of O2 : 32 3. C2H5Cl2: 61.4/100 = 0.614 O2: 84.6/32 = 2.64 4. 4:13 5. 4:13, always make left side 1, so divide each side by 4. New ratio: 1:3.25 C2H5Cl2:O2 1:3.25 0.614:2.64 C2H5Cl2 is obviously the limiting reagent ANSWER QUESTION 10
1. 33.3 grams of Na 19.4 grams of H2O 2. molar mass of Na: 23 molar mass of H2O : 18 3. Na: 33.3/23 = 1.45 H2O: 19.4/18 = 1.08 4. 2:2 5. 2:2, always make left side 1, so divide each side by 2. New ratio: 1:1 Na:H2O 1:1 1.45:1.08 H2O is obviously the limiting reagent